[xep-support] How to get the column width when it is proportional

From: Myers, Ching <Ching.Myers@ingenix.com>
Date: Mon Dec 06 2004 - 15:41:40 PST


I need to use the column-width as a base variable to derive another value dynamically, I tried to use the function of "from-table-column()", it didn't work. Could someone give me a hint? Please refer to the following codes, thanks.

<fo:table space-before.optimum="3pt">
    <fo:table-column column-width="proportional-column-width(2.5)"/>
    <fo:table-column column-width="proportional-column-width(3.5)"/>
    <fo:table-column column-width="proportional-column-width(20)"/>
            <fo:block><xsl:call-template name="code-left-icons" /></fo:block>
            <xsl:call-template name="codetemplate" />
          <xsl:variable name="column-width"><xsl:value-of select="from-table-column(column-width)" />
          <fo:block><xsl:value-of select="$column-width" /></fo:block>
            <xsl:call-template name="descriptiontemplate" />

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Received on Mon Dec 6 16:27:03 2004

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