[xep-support] Passing param values from command line

From: Geurt Lagemaat (Lagemaat@oriana-automatisering.com)
Date: Thu Jan 30 2003 - 02:59:00 PST

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    Must be simple but I cant find it.

    I have a stylesheet like this:
    <?xml version='1.0' encoding='ISO-8859-1'?>
    <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                    xmlns:fo="http://www.w3.org/1999/XSL/Format" version="1.0">

    <xsl:output method="xml" version="1.0" indent="yes" encoding="ISO-8859-1"/>
    <!-- =============================================================== -->
    <!-- Publication Params -->
    <!-- =============================================================== -->
    <xsl:param name="volume" select="'18'" />
    <xsl:param name="volume.number" select="'1'" />
    <xsl:param name="volume.year" select="'2002'" />
    <xsl:param name="initial.page.number" select="1" />

    I invoke XEP with a batchfile that uses the supplied transform.bat file:
    C:\XEP\transform.bat -xml C:\XEP\Projects\MyProject\source\source.xml -xsl
    C:\XEP\Projects\MyProject\Stylesheets\MyStylesheet.xsl -out
    C:\XEP\Projects\ MyProject\PDF\MyResult.pdf -format PDF

    Now I like to know how to change a stylesheet param by specifying its value
    in the batchfile.

    Does someone have an example?


    Geurt Lagemaat
    Oriana Automatisering

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